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IB物理真题

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2011年11月IB物理(SL)真题PDF下载-paper3

2021-06-18

2011年11月IB物理(SL)真题PDF下载-paper3

A1. This question is about photopic vision and scotopic vision.

(a) State the difference between photopic vision and scotopic vision.

(b) At dusk, the petals of a red flower appear to be much duller than the surrounding leaves.Outline, in terms of the functions of the rod and the cone cells in the retina, the reasons for this observation.

 

A2. This question is about standing waves in an organ pipe.

(a) The diagram shows an organ pipe that is open at both ends.

The pipe is emitting its lowest frequency note.On the diagram above,

(i) sketch a representation of the standing wave set up in the pipe.

(ii) label with the letter P, the point or points within the pipe where the air pressure is a maximum.

(iii) label with the letter A, the displacement antinodes.

(b) The length of the pipe in (a) is 1.5 m. An organ pipe that is closed at one end has the same lowest frequency note as the pipe in (a).

Show that the length of this pipe is 0.75 m.

 

A3. This question is about diffraction and polarization.

(a) Light from a monochromatic point source S1 is incident on a narrow, rectangular slit.

After passing through the slit the light is incident on a screen. The distance between the slit and screen is very large compared with the width of the slit.

(i) On the axes below, sketch the variation with angle of diffraction θ of the relative intensity I of the light diffracted at the slit.

(ii) The wavelength of the light is 480 nm. The slit width is 0.1 mm and its distance from the screen is 1.2 m. Determine the width of the central diffraction maximum observed on the screen.

(b) Judy looks at two point sources identical to the source S1 in (a). The distance between the sources is 8.0 mm and Judy’s eye is at a distance d from the sources. Estimate the value of d for which the images of the two sources formed on the retina of Judy’s eye are just resolved.

(c) The light from a point source is unpolarized. The light can be polarized by passing it through a polarizer.Explain, with reference to the electric (field) vector of unpolarized light and polarized light, the term polarizer.

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